Question

1. Impartiti numarul 3804 in parti invers proportinale cu 0,(6) ; 0,75 ; 0,8 ; 0,8(3) .



2. Numerele a si b sunt invers propozitionale cu 6 si 15 . Cat la suta din a reprezinta b ?

Answer 1

0,(6)=6/9=2/3
0,75=75/100=3/4
0,8=8/10=4/5
0,8(3)=83-8/90=75/90=5/6
a=2/3 b=3/4,c=4/5,d=5/6 xd
a+b+c+d=3804
2/3xa=3/4xb =4/5xc+5/6xd=k
2a/3=k =>2a=3k =>a=3k/2
3b/4=k => b=4k/3
4c/5=k=> c=5k/4
5d/6=k =>d=6k/5
3k/2+4k/3+5k/4+6k/5=3.804
aducem la acelasi numitor 60
90k+80k+75k+72k=3804x60
   317k             =228.240
  k=228.240/317
 k=720
 a=3k/2          =>a=3x720/2            =>a=1080
b=4k/3              b=4x720/3                 b=960
c=5k/4              c=5x720/4                 c=900
d=6k/5              d=6x720/5                 d=864
1080+960+900+864=3804
2)a/1/6=b/1/15=k
 6a=15b=>a=15b/6
15/6=2,5
6x250%=15
250% din a=b