Question

1.in triunghiul ABC cu m(A)=90 grade , notam D mijlocul laturi [BC] . Daca AB=6 cm , BC=10 cm si CA = 8 cm, aflati valoarea raportului perimetrelor Pabd si Pacd.
2.In triungiul ABC cu m(A)=90 grade , AB =AC=10 cm si BC = 14 cm , consideram punctele E e (AB) si F e ( AC ) , astfel incat AE=AF =7 cm . aflati EF.

Answer 1

1.AD,mediana
=>conform,t.med.in,tr.drAD=BC/2=5cm
PΔABD=6+5+5=16cm
PΔACD=8+5+5=18cm

$\frac{PABD}{PACD} = \frac{16}{18} = \frac{8}{9}$

2.Avem,ΔFAE,dr(A=90°)
Cu,t.Pit.,aflam,ipotenuza,EF
EF²=7²+7²
EF²=98
EF=7√2cm