Question

1 intreg si 1 pe 3y -1 pe 6y -2,(3)=1,(3)

Answer 1

$\frac{1}{3y} - \frac{1}{6y} - \frac{7}{3} = \frac{4}{3} = > \frac{1}{3y} - \frac{1}{6y} = \frac{11}{3} = > 3 = 66y = > y = 66 \div 3 = > y = 22$