Question

(1-log in baza 3 din 24) log in baza 2 din 3 =-3

Answer 1

(1-$log_{3}24)* log_{2}3=-3$
$log_{2}3- log_{3}24* log_{2}3= log_{2}3-( log_{3}3+ log_{3}8)* log_{2}3=$
=$log_{2}3-(1+3 log_{3}2)* log_{2} 3= log_{2}3- log_{2}3-3=-3$
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