Question

1. Mara a rezolvat cateva exercitii de impartire , iar Teodor a efectuat proba acestora .Observa ce a scris baiatul , apoi scrie ecercitile rezolvate de Mare.
103 x 6 + 4 = 622
98 x9 + 6 + =888
134 x 7 + 6 = 994
273 x 3 +2 = 821


2.Aplica regulile invatate pt a calcula mai usor /
a.867 : 3 - 795 : 3 =
b. 184 : 2 + 368 : 2=
c. 303 : 3 + 606 : 3 + 909 :3 =


VA ROG !!
nu inteleg

Answer 1

1)
622:6=103 rest 4
888:9=98 rest 6
994:7=134 rest 6
821:3=273 rest 2

2)
867:3-795:3=(867-795):3=72:3=24
184:2+368:2=(184+368):2=552:2=276
303:3+606:3+909:3=(303+606+909):3=1818:3=606