Matematică, întrebare adresată de rewride900, 9 ani în urmă

1.
/=modul
/-7/+/2-9/+/-3+8/=
/1+1supra3/-/2 1supra 3/+/7 supa 6=
/1+√2/=√2-3/=
/5supra5-6 supra 7/+/1supra2-3supra5
2.
/x/=3
/x/=0
/x/+1=0
/x/=-√12
/x/-5=0
2 ori /x/=3
3:/x/+/=0
/x/=3 ori /x/
/-x-3/=1
/5-2x/=0
/x+4/=-2

Răspunsuri la întrebare

Răspuns de finamihai
1
1.I-7I+I2-9I+I-3+8I=
ex.Inr.negativI=nr.pozitiv
7+I-7I+I+5I=
7+7+5=19

I1+1/3I-I2 1/3I+I7/6I=
I(3+1)/3I-I(2x3+1)/3I+I7/6I=
I4/3I-I7/3I+7/6=
4/3-7/3+7/6=
-3/3+7/6
(-3x2+7)/6=
(-6+7)/6=1/6

I1+√2I=I√2-3I
I1+
√2I=1+√2
I√2-3I=I3-√2I pt.ca 3>√2
I3-√2I=3-√2

I5/5-6/7I+I1/2-3/5I=
I1-6/7I+I(1x5-3x2)/10I=
I(7-6)/7I+I5-6)/10I=
I1/7I+I-1/10I=
1/7+1/10=
(10+7)/70=17/70

2.
IxI=3
x=3
x=-3
S={-3,3}

IxI=0
x=0
S={0}

IxI+1=0
IxI=-1
x=-1
x=-(-1)=1
S={-1,1}

IxI=-√12
IxI=-2
√3
x=-2√3
x=-(-2√3)=2√3
S={-2√3, 2√3}

IxI-5=0
IxI=5
x=5
x=-5
S={-5,5}

2 IxI=3
IxI=3/2
x=3/2
x=-3/2
S={-3/2,3/2}

3)
I-x-3I=1
-x-3=1
-x=1+3
-x=4      inmultim -1
x=-4
-x-3=-1
-x=-1+3
-x=2    inmultim -1
x=-2
S={-4,-2}

I5-2xI=0
5-2x=0
-2x=-5 inmultim -1
2x=5
x=5/2
-(5-2x)=0
-5+2x=0
2x=5
x=5/2
S={5/2}

Ix+4I=-2
x+4=-2
x=-2-4
x=-6
x+4=-(-2)
x+4=2
x=2-4
x=-2
S={-6,-2}
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