Question

1.O bila de cupru cu masa de 500 g si temperatura de 120°C se intruduce in 2 kg de apa cu temperatura de 10°C.Considerand sistemul izolat,aflati temperatura de echilibru.​

Answer 1

m₁=500 g=0,5 kg

c₁=380 J/kgK

c₂=4200 J/kgK

Qced=m₁c₁(t₁-θ)

Qprim=m₂c₂(θ-t₂)

Qced=Qprim=>m₁c₁(t₁-θ)=m₂c₂(θ-t₂)<=>0,5*380(120-θ)=2*4200(θ-10)<=>22800-190θ=8400θ-84000<=>106800=8590θ=>θ=106800/8590=12,53°C