Question

1) Paranteza patrata (-1)³-8²:(-4)³+2 inchide paranteza patrata * 1999 la puterea 2015=
2)5(x-1)=4(3-x)+7
3) E(x)=x²/x²-2x+1 * x²-1/x=
Aratati:a) forma simpla
b)E(2)=




4)Aflati aria si perimetrul patratului cu diagonala de 4√2.

Answer 1

1) [(-1)³-8²:(-4)³+2]* 1999²⁰¹⁵=
= [-1-64:(-64)+2]* 1999²⁰¹⁵=
= (-1+1+2)* 1999²⁰¹⁵=
=2*1995²⁰¹⁵
2)5(x-1)=4(3-x)+7
5x-5=12-4x+7
9x=19+5
9x=24
x=24/9
x=8/3

3) E(x)=x²/(x²-2x+1) * (x²-1)/x=
=x/(x-1)² * (x+1)(x-1)/1=
=x/(x-1) * (x+1)=
=x(x+1)/(x-1)

b)E(2)=2(2+1)(2-1)=2*3*1=6


4)Aflati aria si perimetrul patratului cu diagonala de 4√2.
diagonala =L√2=4√2
L=4
A=4*4=16
P=4+4+4+4=16