Question

1/radical 9+radical 8+radical 6/radical 6+radical 3+1/radical r+3+1/radical 3+radical2+1/radical 2+1=?
Va roog!!!

Answer 1

$\frac{1}{3} + 2 \sqrt{2} + 1 + \frac{ \sqrt{3 + 1} }{ \sqrt{r + 3} } - \frac{ \sqrt{3} }{3} + 1 \\ \\ \frac{1}{3} + 2 \sqrt{2 } + 2 + \frac{ \sqrt{4} }{ \sqrt{r + 3} } - \frac{ \sqrt{3} }{3 } \\ \frac{7}{3} + 2 \sqrt{2} + \frac{2}{ \sqrt{r + 3} } - \frac{ \sqrt{3} }{3} \\ \frac{7 \sqrt{r + 3 } + 6 \sqrt{(r + 3) \times 2} + 6 - \sqrt{(r + 3) \times 3} }{3 \sqrt{r + 3} } \\ \frac{7 \sqrt{r + 3} + 6 \sqrt{2r + 6} + 6 - \sqrt{3r + 9} }{3 \sqrt{r + 3} }$

buna ,sper ca te am ajutat !!