Question

1) Radical din x+1 = radical din x^2-x-2
Va rog.

Answer 1

x+1=$x^{2}$-x-2
x+1+x+2=$x^{2}$
3+x=$x^{2}$

Answer 2

rezulta (√(x+1))²=(√(x²-x-2))²
x+1=x²-x-2
-x²+x+x+1+2=0
-x²+2x+3=0      inmultim -1
x²-2x-3=0
Δ=4+12=16
x1=(2-4)/2=-2/2=-1
x2=(2+4)/2=6/2=3
S={-1,3}