Question

1.Raționalizați numitorii următoarelor rapoarte.
Rezolvare completă, mulțumesc ​

Answer 1

a) $\it ~^{\sqrt{3}) } \frac{3}{\sqrt{3} } = \frac{ \not 3\sqrt{3} }{\not 3} = \sqrt{3}$

b) $\it  \frac{6}{\sqrt{18} } = ~^{\sqrt{2} )} \frac{6}{3\sqrt{2} } = \frac{6\sqrt{2} }{3 \cdot 2} = \frac{ \not 6\sqrt{2} }{\not 6} = \sqrt{2}$

c) $\it \frac{\sqrt{27} }{6\sqrt{2} } = \frac{3\sqrt{3} }{6\sqrt{2} } = ~^{\sqrt{2} )}  \frac{\sqrt{3} }{2\sqrt{2} } = \frac{\sqrt{6} }{2 \cdot 2} = \frac{\sqrt{6} }{4}$

j) $\it - ~^{\sqrt{3}) } \frac{12}{\sqrt{3} } = -\frac{12\sqrt{3} }{3 } = -4\sqrt{3}$

k) $-\frac{3}{\sqrt{27} } = - \frac{\not 3}{\not 3\sqrt{3} } = -~^{\sqrt{3}) } \frac{1}{\sqrt{3} } = \frac{\sqrt{3} }{3}$

l) $\it \frac{2\sqrt{3} }{\sqrt{8} } = \frac{\not 2\sqrt{3} }{\not 2\sqrt{2} } = ~^{\sqrt{2}) } \frac{\sqrt{3} }{\sqrt{2} } = \frac{\sqrt{6} }{2}$

o) $\it \frac{a\sqrt{b} }{b\sqrt{a} } \cdot \frac{\sqrt{a} }{\sqrt{a} } = \frac{a\sqrt{b} \cdot \sqrt{a}  }{b\sqrt{a} \cdot \sqrt{a}  } = \frac{a\sqrt{ab} }{b \cdot a} =\frac{\sqrt{ab} }{b}$