Question

1]Rezolvati ecuatiile
a]108:x=18                           b] 72:x+2=6 
2]rezolvati in multimea numerelor naturale inecuatia 3[x+1]≤137-131
3] Rezolvato in multimea numerelor naturale $3^{x+1} \leq 81.$
4]Rezolvati in multimea numerelor naturale ecuatia
3*{10+2*[40-2*(28-3*5)]}-7*=51
ajutor!

Answer 1

a)108:x=18 .x=108:18 .x=6 b)72:x+2=6 . 72:x=4 .x=72:4 .x=18 .. ....2) 3(x+1)<=137-131 .3x+3<=6 .3x=6-3 .3x=3 .x=1 ..... ......3)3^x+1<=81 .3^X×3<=81 .3^X=81:3 .3^X=27 . X=3...... .......4) 3×{10+2×[40-2×(28-3×5)]}-7×9=51 . ............3×{10+2×[40-2×(28-15)]}-63=51 . .............3×[10+2×(40-2×13)]-63=51 . ............3×[10+2×(40-26)]-63=51 . .............3×(10+2×14)-63=51 . .............3×(10+28)-63=51 .3×38-63=51 .114-63=51