Question

1. Rezolvati in multimea numerelor naturale ecuatia:
(3x-6)(4x-3)=0


2. Determinati valorile lui x din:
a) [200-(64+x●12+2●11)]●(50-24●2+13●5-9●5)=1980

b) [(32●66●2:24-125):3+5●x]-24●3+888:8=61

Answer 1

[1. (3x-6)(4x-3)=0 rezulta: a) 3x-6=0 rezulta 3x=6 rezulta x=6/3=2 b) 4x-3=0 rezulta 4x=3 rezulta x=3/4 2. a) [200-(64+x*12+2*11)]*(50-24*2+13*5-9*5)=1980 [200-(64+12x+22)]*(50-48+65-45)=1980 (200-86-12x)*22=1980 114-12x=1980:22=90 12x=114-90=24 x=24:12=2 b) [(32*66*2:24-125):3+5x]-24*3+888:8=61 [(32*132:24-125):3+5x]-72+111=61 [(4224:24-125):3+5x]+39=61 [(176-125):3+5x]=61-39=22 51:3+5x=22 17+5x=22 5x=22-17=5 x=5:5=1

Answer 2

(3x-6)(4x-3)=12x²-9x-24x+18=12x²-33x+18
2)a)
[200-(64+x·12+2·11)]·(50-24·2+13·5-9·5)=1980
[200-(64+12x+22)]·(50-48+65-45)=1980
[200-(12x+86)]·22=1980
200-12x-86=1980:22
-12x=90-200+86
-12x=-24    (-1)
x=24/2
x=2

b)
 [(32·66·2:24-125):3+5·x]-24·3+888:8=61
[(4224:24-125):3+5·x]-72+111=61
[(176-125):3+5x]=61+72-111
[51:3+5x]=22
17+5x=22
5x=22-17
5x=5
x=5/5
x=1