Question

1)rezolvati in multimea numerelor naturale inecuati:
3(x+1)<137-131
2)rezolvati in multimea numerelor naturale ecuatia:
3x(10+2x(40-2x(28-3x5))-7x=51

Answer 1

1) 3(x+1)<137-131
    3x+137<131-1 
    140x<130
     x<140/130
     x<1,0
 
2)