Question

1.Rezolvati in multimea numerelor reale :
a) x(x-2)=x²
b) (x-1)(x-3)=x²+3x
c) (3x-1)(3x+1)=9x²+x+1
d) (4x-3)x = (-2x + 0,5 )²
e) 3x² - (√3 x - 1 )² = √3x - 1
f) ( 0,5 y -1 ) ($\frac{1}{2}$ y +1) = 0,25 (y+1)²
g) (4x-1)² +(3x+2)² = ( 5x-1 + √2 )²
h) x(√2-1) + ( x+ 1) ( √3 - √2 ) + ( x + 2) ( 2 - √3 ) = 3 - √2 -√3

Answer 1

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