Question

1)rezolvati prin metoda reducerii urmatoarele sisteme:
a)4x-2(y+1)=2
3x-2y=1
b)4x+y=-16
2(x-2)-3y=2
c)3(x+4)=4(y+3)
2(x-2)=y+1
2)rezolvati prin metoda reducerii sistemele:
a)4(x+2)+3(y+1)=15
5(x+1)+4y=11
b)2(x+1)-3(y-1)=-1
5(x-2)-4(y-3)=1
c)3(x+y)+2(y-x)=-5
4(x-y)-2(2x-y)=4

Answer 1

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