Question

1. RezolvTi problemele : a). (6+a) :5=2. b). (b-48) :2=2 . c). (224-200):c= 8

Varog ajutatima

Answer 1

$\rm (6+a) :5=2|\cdot 5 \\ 6+a=10|-6 \\ \bold{a=4} \\ \\ (b-48) :2=2|\cdot 2 \\ b-48=4 \\ \bold{b=52} \\ \\ (224-200):c= 8 \\ 24:c=8 \\ \bold{c=3}$

Answer 2

a) ( 6+a) = 5 x 2
(6+a) = 10 
6 + a = 10 | -6
a = 6
b) (b-48) = 2x2 
(b - 48) = 4
b - 48 = 4 | +48
b = 52
c) (224 - 200) : c = 8
24 : c = 8 => c = 24 : 8 
c = 3