Question

1. Sa se afle compozitia procentuala a compusul cu formula moleculara C6 H4 N2 O4 stiind ca AC=12 AH=1 AN=14 AO=16

Answer 1

Răspuns:

M C6 H4 N2 O4 =6×12+4×1+2×14+4×16=144g/mol

144g C6H4N2O4..............72gC............4gH............28gN..............64gO

100g C6H4N2O4.............xgC..............ygH.................zgN..............tgO

x=100×72/144= calculeaza

y=100×4/144= calculeaza

z=28×100/144=calculeaza

t=64×100/144= calculeaza

Explicație: