Question

1. sa se afle patru numere naturale consecutive care au suma 630

Answer 1

156,157,158,159 acestea sunt nr

a+a+1+a+2+a+3=630
4a+6=630
4a=630-6
4a=624
a=156
b=a+1=157
c=b+1=158
d=c+1=159

Answer 2

Fie:
x= I nr
x+1= II nr
x+2= III nr
x+3=IV nr
Rezolvare:
x+x+1+x+2+x+3=630
4x+6=630
4x=630-6
4x=624
x=624:4
x=156= I nr

II nr= x+1= 156+1=157
III nr= x+2=156+2=158
IV nr= x+3= 156+3=159