Matematică, întrebare adresată de Doom, 9 ani în urmă

1) Sa se calculeze : 

a) 40-2,25
b) 1,35 - 0,4 
c) 22,14+3,5-1,952
d) 0,3 · 20+4,2·1,8
e) 100-15,92+3·7,8
f) 16,2:3+49,5:0,33
g) 0,003:1,5·100
h)3,56+14,125
i) 2,35-1,715
j) 2,(3)+4,05
k)19,(2)-17,(17)
l)  \frac{1}{2} ·0,(20)
m)0,(741): \frac{10}{9990}
n) 1,04(3) + 2 · 15,(14)
o) 2,5·9,6:0,015

2) Calculati : 

a) 7x+10x-15+2-8x
b) 2a^2 - 4a+a^2-a+7
c)3x^2+3x-2x(x-1)+2
d) (2x-1)(4-2x)
e) 2x(3-5x)-4(x^2+3x-1)
f)(x-1)(2x+1)-2x^2
g) (3u-5)^2
h) (m+4)^2
i) (c-1)^2+2(5c-2)^2
j)v^2 - (2v+6)^2
k) (3x+5y+z)^2

MERSI!!!


Doom: Ps: as vrea si etapele rezolvarii

Răspunsuri la întrebare

Răspuns de finamihai
1
a) 40-2,25=40,00-2,25=37,75
b) 1,35 - 0,4 =1,35-0,40=0,95
c) 22,14+3,5-1,952=25,640-1,952=23,688
d) 0,3 · 20+4,2·1,8=6,00+7,56=13,56
e) 100-15,92+3·7,8=100,00-15,92+23,4=84,08+23,40=107,48
f) 16,2:3+49,5:0,33=5,4+150,0=155,4
g) 0,003:1,5·100=0,02·100=2
h)3,56+14,125=3,560+14,125=17,685
i) 2,35-1,715=2,350-1,715=0,635
j) 2,(3)+4,05=(23-2)/9+405/100=21/9+405/100=7/3+81/20=(20·7/60+81·3/60)=(140+243)/60=383/60=6,38(3)
k)19,(2)-17,(17)=(192-19)/9-(1717-17)/99=173/9-1700/99=(173·11-1700)/99=
=(1903-1700)/99=203/99=2,(05)
l) ·0,(20)=1/2·20/99=10/99=0,(10)
m)0,(741):=741/999:1/999=741/999·999/1=741
n) 1,04(3) + 2 · 15,(14)=(1043-104)/900+2·(1514-15)/99=939/900+2·1499/99=
=313/300+2998/99=(313·33+2998·100)/9900=(10329+299800)/9900=310129/9900=31,326(16)
o) 2,5·9,6:0,015=24:0,15=24:15/100=24·100/15=160

2) Calculati : 

a) 7x+10x-15+2-8x=17X-8X-13=9X-13
b) 2a^2 - 4a+a^2-a+7=A²-5a+7
c)3x^2+3x-2x(x-1)+2=3x²+3x-2x²+2x+2=x²+5x+2
d) (2x-1)(4-2x)=8x+4x-4+2x=14x+4
e) 2x(3-5x)-4(x^2+3x-1)=6x-10x²-4x²-12x+4=-14x²-6x+4
f)(x-1)(2x+1)-2x^2=2x²+x-2x-1-2x²=-x-1
g) (3u-5)^2=9u²-30u+25
h) (m+4)^2=m²+8m+16
i) (c-1)^2+2(5c-2)^2=c²-2c+1+50c²-40c+8=51c²-42c+9
j)v^2 - (2v+6)^2=v²-4v²-24v-36=-3v²-24v-36
k) (3x+5y+z)^2=9x²+15xy+3xz+15xy+25y²+5yz+3xz+5yz+z²=9x²+25y²+z²+30xy+10yz+6z

Doom: g) 0,003:1,5·100=0,02·100=2 ... e bine? nu ai gresit? :P ca nu prea inteleg de ce e 2
finamihai: 0,003=3/1000
finamihai: 3/1000:15/10=3/1000x10/15 simplificam=1/500=0,002, mai trebuia pus un 0
finamihai: incearca sa rezolvi singur, numai asa poti invata
Doom: asta fac acum :) mersi
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