Question

1 Sa se calculeze cate grame de metan corespund la
a) 4 cg H
b) 80 g H
c) 160 g H
d) 36 g C
2 Sa se calculeze cate grame de hidrogen se gasesc in
a) 180 g apa
b) 160 CH3
c) 340 g NH3

Answer 1

1. M CH4= 12+4= 16 g/mol
a) 16 g metan...4 g H
b) 16 g metan...4 g H
x g metan...80 g H
x=16*80/4=320 g metan
c) 16 g metan...4 g H
x g metan...160 g H
x=16*160/4=640 g metan
d) 16 g metan...12 g C
x g metan...36 g C
x= 36*16/12=48 g metan
2. a) M H2O= 2+16=18 g/mol
18 g apa...2 g H
180 g apa...x g H
x=180*2/18=20 g H
b) M CH4= 12+4=16 g/mol
16 g CH4...4 g H
160 g CH4...x g H
x=160*4/16=40 g H
c) M NH3= 14+3= 17 g/mol
17 g NH3...3 g H
340 g NH3...x g H
x=340*3/17=60 g H