Question

1. Sa se efectueze radical din 360 + radical din 40.
2.Sa se calculeze (2x+5) la puterea a 2 a.
3. x/7+x+1/2=9/7
Va rog cu tot cu toata rezolvarea.
Am ramas corigent la mate va rog un sfat,

Answer 1

$1) \\ \\ \sqrt{360} + \sqrt{40} = 6 \sqrt{10} + 2 \sqrt{10} = 8 \sqrt{10}$

2)

(2x+5)²=

(2x)²+2•2x•5+5²=

2²x²+2•2x•5+5²=

4x²+2•2x•5+25=

4x²+20x+25

$3) \\ \\ \frac{x}{7} + x + \frac{1}{2} = \frac{9}{7} \\ \\ \frac{8x}{7} + \frac{1}{2} = \frac{9}{7} \\ \\ \frac{8x}{7} = \frac{9}{7} - \frac{1}{2} = \frac{11}{14} \\ \\ 8x = \frac{11}{14} \times 7 = \frac{77}{14}^{(7} = \frac{11}{2} \\ \\ x = \frac{ \frac{11}{2} }{8} = \frac{11}{2 \times 8} = \frac{11}{16}$

Answer 2

1.

√360 + √40 =

√36×√10 + √4×√10 =

6√10 + 2√10 =

8√10

2.

(2x + 5)² =

(2x)² + 2×2x×5 + 5² =

4x² + 20x + 25

3.

x/7  +  x  +  1/2 = 9/7    /×14

2x + 14x + 7 = 18

16x + 7 = 18

16x = 18 - 7

16x = 11

x = 11/16

x/7  + (x+1)/2 = 9/7   /×14

2x + 7x + 7 = 18

9x = 18 -7

9x = 11

x = 11/9