Question

1. Sa se faculeze procentul de fier (Fe) si proncentul de sulf (S) din 200 de grame de sulfura de fier (FeS)

Answer 1

M=masa moleculara(miu)
M FeS=A Fe+ A S=56+32=88g/mol

88........56g Fe......32 g S
200g....a gFe....b g S
a=200·56:88=127,27 g Fe
b=200·32:88=72,72 g S

200...127,27g Fe...72,72g S
100.......x .........y

x=(100·127,27):200= % Fe
y=(100·72,72):200= % S