Question

1 scoate factorul comun:

a) 2*a+2*b+2*c; b) 5*x+5*y-5*z c) 7*a+7*b+49; d) 3*x-3*y+3

2 daca x=3 si y+z=10,calculeaza

a) 7*x+7*y+7*z; b) 17*x+17*y+17*z-10; c) 5*x+10*y+10*z; d) 100*x-(9*y+9*z).

3 determina catul si restul umatoarelor impartiri a) 2348:15,b) 125 673:32,c) 987:123.

va rog sa ma ajutati si pe mine

Answer 1

1)
2×a+2×b+2×c=
2×(a+b+c)

5×X+5×Y-5×Z=
5×(X+Y-Z)

7×a+7×b+49=
7×(a+b+7)

3×X-3×Y+3=
3×(X-Y+1)

2)
x=3
y+z=10

a) 7*x+7*y+7*z=
7×(X+Y+Z)=
7×(3+10)=
7×13=
91

b) 17*x+17*y+17*z-10=
17×(X+Y+Z)-10=
17×(3+10)-10=
17×13-10=
221-10=
211

c) 5*x+10*y+10*z=
5×(X+Y+Z)=
5×(3+10)=
5×13=
65

d) 100*x-(9*y+9*z)=
100×3-9×(Y+Z)=
300-9×10=
300-90=
210

3)
a) 2348:15=156 rest 8

b) 125 673:32=3 927 rest 9

c) 987:123= 8 rest 3