Question

1.Scrie urmatoarele numere sub forma unei singure puteri,folosind regula de ridicare a unei puteri la o alta putere:
a)(3^4)^7
b)(13^8)^9
c)(17^3)^18
d)(7^11)4
e)(16^8)^6
f)(5^4)3


2.Aplicand regula de inmultire a puterilor cu acelasi exponent,scrieti sub forma unei singure puteri numerele
a)3^16x7^16
b) 5^4x2^4
c)15^12x11^12
d)7^10x5^10
e)2^34x5^34x7^34
f)6^30x7^30x2^30


Va roggg dauuu si coroanaaa!!!!!

Answer 1

1)
a)(3^4)^7 = 3^28
b)(13^8)^9 = 13^72
c)(17^3)^18 =  17^54
d)(7^11)^4 =  7^44
e)(16^8)^6 = 16^48
f)(5^4)^3 =5^12

2)
a)3^16x7^16 = (3x7)^16 = 21^16
b) 5^4x2^4 =(5x2)^4 = 10^4
c)15^12x11^12 = (15x11)^12 = 165^12
d)7^10x5^10 = (7x5)^10 = 35^10
e)2^34x5^34x7^34 = (2x5x7)^34 = 70^34
f)6^30x7^30x2^30 = (6x7x2)^30 = 84^30

Answer 2

1)
(a^b)^n=a^b•n

(3^4)^7=3^4•7=3^28

(13^8)^9=13^8•9=13^72

(17^3)^18=17^3•18=17^54

(7^11)^4=7^11•4=7^44

(16^8)^6=16^8•6=16^48

(5^4)^3=5^12

2)
a^m•b^m=(a•b)^m

3^16•7^16=(3•7)^16=21^16

5^4•2^4=(5•2)^4=10^4

15^12•11^12=(15•11)^12=165^12

2^34•5^34•7^34=(2•5•7)^34=70^34

6^30•7^30•2^30=(6•7•2)^30=84^30