Question

1)Scrieti ecuatia unei reactii chimice care justifica afirmatia:
''Bromul are caracter nemetalic mai puternic decat iodul''
2)Calculati cocentratia procentuala masica a solutiei obtinute prin adaugarea a 30g de iodura de potasiu si a 20g de apa distilata peste 450g de solutie de iodura de potasiu de concentratie procentuala masica 10%.
3)Scrieti ecuatia unei reactii chimice care justifica afirmatia;
''Acidul clorhidric este un acid mai tare decat acidul cianhidric.''

Answer 1

1) 2NaI + Br₂ -> 2NaBr + I₂
3) acizii slabi sunt deplasati din saruri de acizii tari:
    HCl + KCN -> KCl + HCN
2) iti dau o formula: ms1/ms2=(c2-cf)/(cf-c1)
c1=miodura*100/(miodura+mapa)=md1*100/ms1=30*100/50=60%
ms1(cf-c1)=ms2(c2-cf) => ms1*cf-ms1*c1=ms2*c2-ms2*cf => cf(ms1+ms2)=ms1*c1+ms2*c2 => cf=(ms1*c1+ms2*c2)/(ms1+ms2)=(50*60+450*10)/500=7500/500=15%