Question

1.se amesteca continutul celor 3 pahare.Ce concentratie va avea solutia
pahar 1:25 g HCL,c=10%
pahar 2: 48g HCL,c=15%
pahar 3: 80 g H20

Answer 1

Răspuns:

ms1=25g

c1=10% => md1=(C1×ms1)/100=10×25/100= 2.5g HCl

md2=7.2g HCl

mh2o=80g

md final=md1+md2=2.5+7.2=9.7g HCl

msf =ms1+ms2+mh2o=25+48+80=153 g

c finala =(mdf×100)/msf=6.33 ~ 6.34%

md2 il calculezi după formula folosită la md1, doar schimband datele

verifică calculele!!!