Question

1 si 2 va rog frumos dau coroana

Answer 1

m(∡B)=2/3×m(∡A)
m(∡C)=1/6×m(∡A)
m(∡D)=1 1/4×m(∡B)=5/4×m(∡B)=5/4×2/3×m(∡A)=5/6×m(∡A)
m(∡A)+m(∡B)+m(∡C)+m(∡D)=360°
notam m(∡A)=a
m(∡A)+2/3×m(∡a)+1/6×m(∡A)+5/6×m(∡A)=360°
a+2a/3+a/6+5a/6=360°
6a+4a+a+5a=2160°
16a=2160°
a=135°
m(∡A)=135°
m(∡B)=2/3×135°=90°
m(∡C)=1/6×135°=22,5°=22° 30'
m(∡D)=5/4×90°=112,5°=112° 30'


2.
m(∡B)=75°
0,1(6)=(16-1)/90=15/90=1/6
0,25=1/4
0,1(1)=(11-1)/90=10/90=1/9
m(∡A)/6=m(∡C)/4=m(∡D)/9     
m(∡C)=4×m(∡A)/6= 2×m(∡A)/3  .
m(∡D)=9×m(∡A)/6=3×m(∡A)/2
m(∡A)+m(∡B)+m(∡C)+m(∡D)=360°
notam m(∡A)=a
a+75°+2a/3+3a/2=360°
6a+4a+9a=1710°
19a=1710°
a=90°
m(∡A)=90°
m(∡C)=2×90°/3  =60°
m(∡D)=3×90°/2=135°