Question

1) Stiind ca 3x+2y+4z=30.Determinati 4z+43+2y+27+3x

2) Stiind ca x+3+y+4+z+5=12.Determinati 2012+x+y+2

3) Stiind ca 2x+2y+45=59.Determinati 4y+4x+32
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Answer 1

3x+2y+4x=30
4z+43+2y+27+3x= 3x+2y+4z+70=30+70=100

x+3+y+4+z+5=12
x+y+z=0
2012+x+y+z=2012

2x+2y+45=59
2x+2y=59-45=14
4x+4y=28
4x+4y+32=28+32=60

Answer 2

1)4z+43+2y+27+3x=4z+2y+3x+43+27=30+43+27=100 am inlocuit prima egaliatet in a doua, in loc de 4z+2y+3x =30
2)x+3+y+4+z+5=12
x+y+z+12=12, x+y+z=0, 2012+x+y+2 ? pe semne ai scapatZ?
3) 2x+2y+45=59, de aici 2x+2y=59-45, 2x+2y=14, x+y=7
4x+4y=28, 4x+4y+32=28+32=60