Question

1.Stiind ca numerele a,b,c au suma egala cu 9,adica a+b+c,calculeaza:
5×(a+b+c)=
(a+b+c)×7=
15×(a+b+c)=
11×a+11×b+11×c=
23×a+23×b+23×c=
6×(a+b+c)+46=
81-(a+b+c)+8=
19×a+19×b+19×c-71=​

Answer 1

5•9=45
9•7=63
15•9=135
11•9=99
23•9=207
6•9+46=100
81-9+8=80
19•9-71=100

Spor la teme ✩

Answer 2

a + b + c = 9

5 × ( a + b + c ) =

5 × 9 = 45

( a + b + c ) × 7 =

9 × 7 = 63

15 × ( a + b + c ) =

15 × 9 = 135

11 × a + 11 × b + 11 × c =

11 × ( a + b + c ) =

11 × 9 = 99

23 × a + 23 × b + 23 × c =

23 × ( a + b + c ) =

23 × 9 = 207

6 × ( a + b + c ) + 46 =

6 × 9 + 46 =

54 + 46 = 100

81 - ( a + b + c ) + 8 =

81 - 9 + 8 =

72 + 8 = 80

19 × a + 19 × b + 19 × c - 71 =

19 × ( a + b + c ) - 71 =

19 × 9 - 71 =

171 - 71 = 100