Question

1.suma a 5 nr consecutive impare este 65. afla nr
2.6 nr. consecutive au suma 75 .Afla numarele.

Answer 1

1.65-5=60 : 5=12 dupa acea nr sunt 12,13,14,15,16

Answer 2

1)a++a2+a+4+a+6+a+8=65
5a+20=65
5a=65-20=45
a=45:5=9
numerele sunt
9
9+2=11
9+4=13
9+6=15
9+8=17

2)a+a+1+a+2+a+3+a+4+a+5=75
6a+15=75
6a=60
a=60:10
 numerele sunt:
10
11
12
13
14
15