Question

1.Suma a patru nr naturale este 105 stiind ca al patrulea nr este 15,iar primele trei sunt nr pare consecutive.Afla cele trei nr.

2.Calculati:
{(247+363:11):(36x6-848:4)+180:6}:(48:6+4x3)

Answer 1

1) 105-15=90
x+(x+2)+(x+4)=90
3x+6=90
3x=84
x=28
x+2=30
x+4=32

R/s Al treilea nr este 32

2) [(247+363/11):(36*6-848/4)+180/6]:(48:6+4*3)
    [(247+33)/(216-212)+30]:(8+12)
    (280/4+30)/20
    100/20=5

R/s: 5

Answer 2

1)
a+a+2+a+4+15=105
3a+2+4+15=105
3a=105-21
3a=84
a=84:3
a=28
28+2=30
28+4=32
V: 28+30+32+15=105
2)
{(247+363:11):(36x6-848:4)+180:6}:(48:6+4x3)=
{(247+33):(216-212)+30}:(8+12)=
{280:4+30}:20=
(70+30):20=
100:20=5