Question

1 supra 1-i -1 supra 1+i totul la puterea a doua =?

Answer 1

1/(1-i)-1/(1+i)= (1+i-(1-i))/2=2i/2=i
i²=-1
as simple as that!!!!!

Answer 2

N=$\frac{1}{1-i}- \frac{1}{1+i}= \frac{1+i-(1-i)}{(1-i)(1+i)} = \frac{1+i-1+i}{1-i^{2}}= \frac{2i}{2}=i$
N²=i²
N²=-1.