Question

1 supra 12 - 5 supra 18 + 1 supra 9

Vreau rezolvare nu doar raspunsul direct.

Answer 1

$\frac{1}{12}-\frac{5}{18}+\frac{1}{9}=\frac{1\cdot \:3}{12\cdot \:3}-\frac{5\cdot \:2}{18\cdot \:2}+\frac{1\cdot \:4}{9\cdot \:4}=\frac{3}{36}-\frac{10}{36}+\frac{4}{36}=\frac{3-10+4}{36}=-\frac{3}{36}=-\frac{1}{12}$

Answer 2

$\it \dfrac{^{3)}1}{\ 12} - \dfrac{^{2)}5}{\ 18} +\dfrac{^{4)}1}{\ 9} =\dfrac{3-10+4}{36}=\dfrac{7-10}{36}=\dfrac{-3^{(3}}{36} = -\dfrac{1}{12}$