Question

(1 supra 2 - 1 supra 6 : 1 supra 3) la 2009

Answer 1

$( \frac{1}{2} - \frac{1}{6}: \frac{1}{3} )^2^0^0^9=\ \textgreater \ ( \frac{1}{2} - \frac{1}{6} * \frac{3}{1} )^2^0^0^9=\ \textgreater \ ( \frac{1}{2}- \frac{1}{2} ) ^2^0^0^9=\ \textgreater \ 0$