Question

[(1 supra 2+ 2 supra 3 + 5 supra 6)÷7 supra 12 - 2 supra 5 × 5 supra 6]× 1 supra 4 ÷(5 × 12 supra 25 - 1 intreg si 1 supra 3) ajutor

Answer 1

   [(1/2+2/3+5/6):7/12 - (2/5)x(5/6)]x(1/4):(5x12/25 - 1si1/3) = 
= [(3/6+4/6+5/6)x12/7 - (2/6)] x (1/4) : (12/5-4/3) = 
 = [(12/6)x12/7 - 1/3] x (1/4) : (36/15-20/15) = 
= (2x12/7 - 1/3) x (1/4) : (16/15) = 
= (24/7 - 1/3) x 1/4 x 15/16 = 
= (72/21 - 7/21) x 1/4 x 15/16 = 
= 65/21 x 1/4 x 15/16 = 
= 65x5/7x4x16 =
= 325/448