Question

[(1 supra 3 minus 1 supra 9) la puterea 2 plus (1 supra 3) la puterea 3] impartit la (1 supra 3) la puterea 4
pls imi trebuie repede

Answer 1

[(1/3-1/9)²+(1/3)³]:(1/3)⁴=

=[(2/9)²+(1/3)³]:(1/3)⁴=

=[4/81+1/27]:(1/3)⁴=

=7/81:1/81=

=7/81×81=

=7

Answer 2

$\it \Big[\Big(\dfrac{^{3)}1}{\ 3}-\dfrac{1}{9}\Big)^2+\Big(\dfrac{1}{3}\Big)^3\Big]:\Big(\dfrac{1}{3}\Big)^4=\Big[\Big(\dfrac{2}{9}\Big)^2+\Big(\dfrac{1}{3}\Big)^3\Big]:\Big(\dfrac{1}{3}\Big)^4=\\ \\ \\ =\Big(\dfrac{4}{81}+\dfrac{^{3)}1}{\ 27}\Big):\dfrac{1}{81}=\dfrac{7}{81}\cdot\dfrac{81}{1}=7$