Question

1 supra x-1 - 2x supra 1-x^2 + 1 supra x+1

Answer 1

$\frac{1}{x-1} - \frac{2x}{1- x^{2} } + \frac{1}{x+1} = \frac{x+1+2x+x-1}{ (x+1)^{2} } = \frac{4x}{ (x+1)^{2} }$
sper ca te-am ajutat!

Answer 2

$\frac{1}{x-1} - \frac{2x}{1-x ^{2} } + \frac{1}{x+1} = \frac{1}{x-1} + \frac{2x}{x ^{2} -1} + \frac{1}{x+1} = \frac{1}{x-1} + \frac{2x}{(x-1)(x+1)} + \frac{1}{x+1} =$ =
$\frac{x +1+2x+x-1 }{(x+1)(x-1)} = \frac{4x}{(x+1)(x-1)}$