Question

1 $\frac{3}{8}$ +(-1)+$\frac{2}{3}$+($\frac{-1}{6}$)=

Answer 1

1[tex] \frac{3}{8} -1+ \frac{2}{3}- \frac{1}{6}= [/tex]
=$\frac{11}{8} -1+ \frac{2}{3}- \frac{1}{6} = \frac{11-24+16-4}{24}= -\frac{1}{24}$
Am adus la acelasi numitor.