Question

1.Transformati in fractii ireductibile
a)2,(3); b)1,(7); c)6,(8); d)7,(2); e)0,(6); f)1,(23); g)2,(35); h)3,(60); i)5,(18); j)6,(72); k)0,(112); l)2,(211); m)1(213); n)3,(312); o)4,(102); p)2,1(3); q)3,2(4) ;r)2,3(7); s)2,3(12); t)3,1(27); u)3,2(6) ;v)12,5(3); x)2,3(31) ;y)27,1(32); z)7,2(65)
Urgent va rog

Answer 1

a) 2,(3) = (23-2)/9 = 21/9 = 7/3 (am simplificat prin 3)

b) 1,(7) = (17-1)/9 = 16/9

c) 6,(8) = (68-6)/9 = 62/9

d) 7,(2) = (72-7)/9 = 65/9

e) 0,(6) = 6/9 = 2/3 (am simplificat prin 3)

f) 1,(23) = (123-1)/99 = 122/99

g) 2,(35) = (235-2)/99 = 233/99

h) 3,(60) = (360-3)/99 = 357/99 = 119/33 (am simplificat prin 3)

i) 5,(18) = (518-5)/99 = 513/99 = 57/11 (am simplificat prin 9)

j) 6,(72) = (672-6)/99 = 666/ 99 = 74/ 11 (am simplificat prin 9)

k) 0,(112) = 112/ 999

l) 2,(211) = (2211-2)/ 999 = 2209/ 999

m) 1,(213) = (1213-1)/ 999 = 1212/ 999 = 404/ 333 (am simplificat prin 3)

n) 3,(312) = (3312-3)/ 999 = 3309/ 999 = 1103/ 333 (prin 3)

o) 4,(102) = (4102-4)/ 999 = 4098/999 = 1366/333 (prin 3)

p) 2,1(3) = (213-21)/90 = 192/ 90 = 32/15 (prin 6)

q) 3,2(4) = (324-32)/ 90 = 292/90 = 146/ 45 (prin 2)

r) 2,3(7) = (237-23)/90 = 214/90 = 107/ 45 (prin 2)

s) 2,3(12) = (2312-23)/990 = 2289/ 990 = 763/ 330 (prin 3)

t) 3,1(27) = (3127-31)/990 = 3096/ 990 = 172/ 55 (prin 18)

u) 3,2(6) = (326-32)/ 90 = 294/ 90 = 49/ 15 (prin 6)

v) 12,5(3) = (1253-125)/ 90 = 1128/ 90 = 188/ 15 (prin 6)

w) lipseşte

x) 2,3(31) = (2331-23)/990 = 2308/ 990 = 1154/ 495 (prin 2)

y) 27,1(32) = (27132-271)/ 990 = 26861/ 990

z) 7,2(65) = (7265-72)/ 990 = 7193/ 990