Question

1)x•a+x•b+x•c=40 a+b+c=10 aflati-l pe x 2)4ax+3bx-2cx=80 si 4a +3b=2c+16 aflati-l pe x

Answer 1

x(a+b+c)=40
x•10=40
x=4
x(4a+3b-2c)=80
4a+3b=2c+16
4a+3b-2c=16
x•16=80
x=5