Question

1)x la puterea a 2 = 9
2)19 minus 3a la puterea a doua =
3) (x+ 1)^2 minus x la puterea a 2 = 5
Va rog ajuatatima!

Answer 1

Răspuns:

1) x= radical din 9 => x= +- (plus minus) 3

2) 19-9=10

3) (x+1)^2 -x^2=5 => x^2+2x+1-x^2=5 => 2x+1=5 => x= 4:2 => x=2

Answer 2

x^2=9

x^2=3^2

=> x=3

19-3^2=19-9=10

(x+1)^2-x^2=5

x^2+2*1x+1^2-x^2=5

x^2+2x+1-x^2=5

2x+1=5 / - 1

2x= 4 / :2

x=2