Question

1.x,y,x=?
(x-1)(y+1)(z-3)=15

2.
[(6x2:12-x:12):1+9:3]x6-24=0

Answer 1

[(6×2:12-x:12):1+9:3]×6-24=0 [(12:12-x:12):1+3]×6-24=0 [(1-x:12):1+3]×6=0+24 [(1-x:12):1+3]×6=24 [(1-x:12):1+3]=24:6 [(1-x:12):1+3]=4 (1-x:12):1+3=4 (1-x:12):1=4-3 (1-x:12):1=1 1-x:12=1 x:12=1-1 x:12=0 x=0×12 x=0 .