Question

10-10:{1+3×[(57-60:4×2):3+21]:10}.


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Answer 1

10-10:{1+3•[(57-60:4•2):3+21]:10}=

10-10:{1+3•[(57-15•2):3+21]:10}=

10-10:{1+3•[(57-30):3+21]:10}=

10-10:{1+3•[27:3+21]:10}=

10-10:{1+3•[9+21]:10}=

10-10:{1+3•30:10}=

10-10:{1+3•3}=

10-10:{1+9}=

10-10:10

10-1=9

Answer 2

Salutare!

$\bf 10-10:[1+3\cdot[(57-60:4\cdot2):3+21]:10]=$

$\bf 10-10:[1+3\cdot[(57-15\cdot2):3+21]:10]=$

$\bf 10-10:{1+3\cdot[(57-30):3+21]:10}=$

$\bf 10-10:[1+3\cdot(27:3+21):10]=$

$\bf 10-10:[1+3\cdot(9+21):10]=$

$\bf 10-10:(1+3\cdot 30:10)=$

$\bf 10-10:(1+90:10)=$

$\bf 10-10:(1+9)=$

$\bf 10-1=$

$\boxed{\bf 9}$

==pav38==