Question

10-10:{1+3ori[(57-60:4ori2):3+21]:10

Answer 1

unde se pune acolada la sfârșit?

10-10:{1+3×[(57-60:4×2):3+21]:10=
=10-10:{1+3×[(57-15×2):3+21]:10=
=10-10:{1+3×[(57-30):3+21]:10=
=10-10:[1+3×(27:3+21):10=
=10-10:[1+3×(9+21):10=
=10-10:(1+3×30:10= nu stiu unde e sfarsitul parantezei
=10-10:(1+3×3=
=10-10:(1+9 =
=10-10:10=
=10-1=
=9