Question

10+10:{[10+10×[(a-10)]:10_10}=11​

Answer 1

Răspuns:

10 + 10 ÷ {[10 + 10 × (a - 10)] ÷ 10 - 10} = 11

10 + 10 ÷ [(10 + 10a - 100) ÷ 10 - 10] = 11

10 + 10 ÷ [(10 - 100 - 10a) ÷ 10 - 10] = 11

10 + 10 ÷ [(-90 - 10a) ÷ 10 - 10] = 11

$10 + 10 \div ( \frac{ - 90 + 10a}{10} - 10) = 11$

$1 0+ 10 \div ( \frac{10 \times ( - 9 + a)}{10} - 10) = 11$

$10 + 10 \div ( \frac{( - 9 + a)}{10 \div 10} - 10) = 11$

10 + 10 ÷ (-9 + a - 10) = 11

$10 + \frac{10}{ - 9 + a - 10} = 11$

$10 + \frac{10}{ - 9 - 10 + a} = 11 = > 10 + \frac{10}{ - 19 + a} = 11$

$\frac{10}{ - 19 + a} = 11 - 10 = > \frac{10}{ - 19 + a } = 1$

10 × 1 = -19 + a

10 = -19 + a

-a + 10 = -19

-a = -19 - 10

-a = -29 / -1

a = 29

Sper ca te-am ajutat!