Question

10, 12 va rog frumos .

Answer 1

Răspuns:

Explicație pas cu pas:

10.

a+b+c=1032

b=3a

c=a/2+60

a+3a+a/2+60=1032

a+3a+a/2=972

2a+6a+a=1944

9a=1944, a=1944/9=216

b=3*216=648

c=216/2+60=108+60=168

12.

patru numere consecutive pot fi de forma x, x+1, x+2, x+3

x+x+1+x+2+x+3=110

4x+6=110

4x=104, x=26