Question

10×{18²:324+2×[(2²×3)¹⁵:(2²⁹×3¹⁵)+1²⁴]} va roggggggggggg​

Answer 1

 

$\displaystyle\bf\\10\times\Big\{18^2:324+2\times [(2^2\times3)^{15}:(2^{29}\times3^{15})+1^{24}]\}=\\\\=10\times\Big\{18^2:324+2\times \Big[\frac{(2^2\times3)^{15}}{(2^{29}\times3^{15})}+1^{24}\Big]\Big\}=\\\\=10\times\Big\{18^2:324+2\times \Big[\frac{2^{2\times15}\times3^{15}}{2^{29}\times3^{15}}+1^{24}\Big]\Big\}=\\\\=10\times\Big\{18^2:324+2\times \Big[\frac{2^{30}\times3^{15}}{2^{29}\times3^{15}}+1\Big]\Big\}=$

.

$\displaystyle\bf\\=10\times\Big\{18^2:324+2\times \Big[2^{30-29}\times3^{15-15}+1\Big]\Big\}=\\\\=10\times\Big\{18^2:324+2\times \Big[2^{1}\times3^{0}+1\Big]\Big\}=\\\\=10\times\Big\{18^2:324+2\times \Big[2\times1+1\Big]\Big\}=\\\\=10\times\Big\{18^2:324+2\times 3\Big\}=\\\\=10\times\Big\{324:324+2\times 3\Big\}=\\\\=10\times\Big\{1+6\Big\}=\\\\=10\times7=70$