Question

10×{24^2:576+3×[(3^2×2)^15:(3^29×2^15)+1^21]}:13
pas cu pas plz pana la ora 12​
dau coroana

Answer 1

Răspuns:

10×{576:576+3×[(3∧30×2∧15):(3∧29×2∧15)+1]}:13=

10×[1+3×(3+1)]:13=

10×(1+3×4):13=

10×13:13=

130:13=10

2∧100×[2∧98+(2∧50×2∧75):2∧27+(5-3)∧90×2∧8+2∧98]=

2∧100×[2∧98+2∧125:2∧27+2∧90×2∧8+2∧98]=

2∧100×(2∧98+298+2∧98+2∧98)=