Question

10-3 supra 2×{2supra3-7×[6-5(2supra3-3)]}
rapid va rog!​

Answer 1

Răspuns:

Explicație pas cu pas:

$10-\frac{3}{2}\cdot\left\{\frac{2}{3}-7\cdot\left[6-5\left(\frac{2}{3}-3\right)\right]\right\}=?\\10-\frac{3}{2}\cdot\left\{\frac{2}{3}-7\cdot\left[6-5\left(\frac{2}{3}-\frac{9}{3}\right)\right]\right\}=?\\10-\frac{3}{2}\cdot\left\{\frac{2}{3}-7\cdot\left[6-5\cdot\left(-\frac{7}{3}\right)\right]\right\}=?$

$10-\frac{3}{2}\cdot\left\{\frac{2}{3}-7\cdot\left[6-\left(-\frac{35}{3}\right)\right]\right\}=?\\10-\frac{3}{2}\cdot\left[\frac{2}{3}-7\cdot\left(6+\frac{35}{3}\right)\right]=?\\10-\frac{3}{2}\cdot\left[\frac{2}{3}-7\cdot\left(\frac{18}{3}+\frac{35}{3}\right)\right]=?$

$10-\frac{3}{2}\cdot\left(\frac{2}{3}-7\cdot\frac{53}{3}\right)=?\\10-\frac{3}{2}\cdot\left(\frac{2}{3}-\frac{371}{3}\right)=?\\10-\frac{3}{2}\cdot\left(-\frac{369}{3}\right)=?\\10-\left(-\frac{1107}{6}\right)=?\\10+\frac{1107}{6}=\frac{60}{6}+\frac{1107}{6}=\frac{{1167}^{(3}}{6}=\boxed{\bold{\frac{389}{2}}}$

Answer 2

$\it 10-\dfrac{3}{2}\cdot \Big\{ \dfrac{2}{3}-7\cdot\Big[6-5\Big(\dfrac{2}{3}-3\Big)\Big]\Big\} =10-\dfrac{3}{2}\cdot \Big[ \dfrac{2}{3}-7\cdot\Big(6+5\cdot\dfrac{7}{3}\Big)\Big] =\\ \\ \\ =10- \dfrac{3}{2}\cdot\Big(\dfrac{2}{3}-\dfrac{371}{3}\Big)=10+\dfrac{3}{2}\cdot\dfrac{369}{3}=10+\dfrac{369}{2}=\dfrac{389}{2}$